00:01
To show that u1, u2, and u3 is a basis, we need to show that the three vectors are linearly independent and that they span our entire vector space.
00:10
So to show that they are linearly independent, we set a system of equation as follows.
00:18
And then if we show that c1, c2, and c3 have to be zero for this equation to hold, that means that u1, u2, and u3 must be linearly independent.
00:28
It.
00:29
So let's plug in our values for u1, u2, and u3.
00:35
Thus u u1, u2, u2, and u3 .s becomes v1, u2, and u3.
00:41
U3 .s .s.
00:42
V1 plus v2 plus v3.
00:44
And now let's group this together by our variables v1, v2, and v3.
00:51
So we have c1 plus c2 plus c2 plus c2 plus c3 plus c3 times v3 must be 0.
01:02
Now recall that v1, v2, and v3 are all linearly independent.
01:08
So that means that c1 plus c2 plus c3 must be 0.
01:12
That means that c2 plus c3 must be zero...