00:01
In order to answer all parts of this particular question, it's helpful to write the inerts equation for a concentration cell.
00:07
The inerts equation for a concentration cell is always of this form, where we have e -cell is equal to e -cell standard, which will always be zero, minus 0 .05916 divided by n, log of, we always have the anode concentration in the numerator and the cathode concentration in the denominator, so that we get a positive e -cell where the anode compartment concentration is always the lower one, and the cathode compartment concentration is always the higher one.
00:41
That way this ratio will be less than one, giving us a log value that is negative, and then with this negative right here, we're going to end up with a positive e -cell, which is what we need for the concentration cell.
00:55
So then it becomes relatively easy.
00:58
E -cell for the first one will be zero because these two concentrations will be 1 and the log of 1 is 0, so everything ends up being 0.
01:08
And then for b, we've got one side with one molar, that will be the anode, and that's a lower concentration divided by the cathode, gives us then an e -cell of 0 .018...