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Consider the decomposition of calcium carbonate: $\mathrm{CaCO}_{3}(s) \rightleftharpoons \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)$Calculate the pressure in atm of $\mathrm{CO}_{2}$ in an equilibrium process (a) at $25^{\circ} \mathrm{C}$ and (b) at $800^{\circ} \mathrm{C}$. Assume that $\Delta H^{\circ}=177.8 \mathrm{kJ} / \mathrm{mol}$ and $\Delta S^{\circ}=160.5 \mathrm{J} / \mathrm{K} \cdot \mathrm{mol}$ for the temperature range.

$0.535$ atm

Chemistry 102

Chapter 17

Entropy, Free Energy, and Equilibrium

Thermodynamics

University of Central Florida

Rice University

University of Maryland - University College

University of Toronto

Lectures

00:42

In thermodynamics, the zeroth law of thermodynamics states that if two systems are in thermal equilibrium with a third system, they are also in thermal equilibrium with each other.

01:47

A spontaneous process is one in which the total entropy of the universe increases. In a spontaneous process, the system will move from an ordered state to a disordered state, such as from ice to water, or from a solid to a gas. The concept of spontaneity was introduced by Rudolf Clausius in 1850.

03:42

Consider the decomposition…

00:53

When calcium carbonate is …

04:26

For the decomposition of s…

08:06

Consider the thermal decom…

11:45

03:31

answer for the question. For the reaction. K P is equal to P or two partial pressure off so, too, and calculation for Part A and 25 degrees Celsius. Delta, she note, is equal to Delta. Age, not minus tree. Belka isnot by putting values behave. 177 0.8 Multiply 10 rest with the power tree Okay, minus 298 Multiply 160.5 Oh, Joel Permal is equal to 1.30 Multiply 10 rest of the power tree Joel permanent. The next partial pressure off CO two is equal to KP is equal toe e exponent Delta Gee note, divided by RT, is equal to E explained one 30 Multiply 10 Dressed to the power three. Divided by 8.314 multiply 298 is equal to eat. Exponent minus 52.47 Yeah, is equal to 1.6. Multiply 10 Wrist with the power 23 At T M Standard atmospheric pressure for Pardon me, it temperature 800 degrees. Else's Delta G not is equal to Delta. It's not minus T. Delta isnot by putting values, we have 177.8 Multiply 10 rest with the power several minus 1073 in 21 62.5 Joel Permal is equal to 5.58 Multiply 10 rest with the power three. Joel Permal. So here way Have partial pressure off. Co two is equal to K P is equal toe e exponents. Delta G note. Divided by RT. Is it well to e exponents? 5.58 multiplied and rest of the power three Divided by 8.314 Multiply 1073 is able to rehab minus 0.6 to 5 is equal to 0.535 Standard. It was very pressure.

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