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Consider the Doppler-shifted hydrogen spectrum received from a rapidly receding galaxy. Construct a problem in which you calculate the energies of selected spectral lines in the Balmer series and examine whether they can be described with a formula like that in the equation $\frac{1}{\lambda}=R\left(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}}\right),$ but with a different constant $R.$

2861 $\mathrm{nm}$ $2.517 \times 10^{6} \mathrm{m}^{-1}$

Physics 103

Chapter 30

Atomic Physics

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

Lectures

02:42

Atomic physics is the fiel…

03:50

In atomic physics, the Rut…

01:27

CosmologyWhat is the o…

01:16

The wavelengths of Fraunho…

04:31

Find the wavelength of the…

03:15

The wavelengths in the hyd…

03:28

Use Balmer's formula …

$\bullet$ Use Balmer'…

05:24

One series of lines of the…

01:58

The spectrum of a distant …

02:45

Some of the familiar hydro…

02:29

In an experiment done in a…

02:12

One of the wavelengths of …

01:18

A galaxy's hydrogen- …

02:24

The wavelengths of a spect…

02:37

Show that the frequency ra…

04:57

The various spectral lines…

03:16

According to the equation …

04:23

04:52

01:28

Calculate the wavelengths …

for a Doppler shift in irreverent we write to lend our Delta Lambda divided by Linda Is it cool to be divided fancy when we use the recessional velocity of a galaxy we can ride to be is equal to Hubble Constant times our distance to the galaxy Ah, then we can finally be by substituting Invent 21.8 times 10 to the power minus three meter for second light ear times 2.4 times 10 to the power eight light Here This gives us we to be me to be five foreign to three times 10 to the power six meter per second. This is a recessional speed from here. Then we can find ah Delta Lambda which will be re divided by sea turns a Lambda Substantive values we get there 11.4, um, nano meter. So the Revlon shift his 11.4 centimeter since the galaxy's receding, the observed revel in these longer than the prevalent in the arrest frame off the galaxy. Therefore, we can write six 56 43 nano meter plus 11.4 nanometer, which gives us 66 eight approximately Nana region

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