00:01
So in this problem we have two charges that are around the origin of the xy plane, and they are distance a from the origin, both of them.
00:19
Then we have some point p that is on the distance of 1x from the origin.
00:29
And we need to find the electric field, the total electric field vector at the point p.
00:36
That is coming from both the positive and the negative charged particle.
00:41
Now the vector field coming from the negative charged q is going to be e1.
00:52
We call it in e1 and it is oriented towards the negative horizontal direction.
01:00
So this is e1.
01:04
And electric field vector coming from the positive charge is e2.
01:11
And it is directed towards the positive direction of the horizontal axis.
01:16
This is actually e2.
01:22
The net field will exist in the point p because the electric field vector coming from minus q and plus q will be different from one another due to fact that, due to fact that both of charges are not equally distant from the point p...