00:01
So now we'll work on prop 14 from chapter 8.
00:07
In this problem, we're asked to consider the element sodium, silicon, and phosphorus, and answer some questions about their properties.
00:24
So let's go ahead and write the elements up here.
00:26
We have sodium, magnesium, aluminum, silicone, and phosphorus.
00:34
In part a, we're asked, which has the highest second ionization energy? so which element is it hardest to remove a second electron? so here, all sodium, magnesium, and aluminum all have low ionization energies because we expect that to be easy for them to remove the electrons.
01:12
So that's the case for magnesium and aluminum because we want to lose two electrons in magnesium, two electrons in aluminum, three electrons in aluminum.
01:21
Silicon and phosphorus, we want to gain electrons, but we also can easily remove those electrons as well.
01:29
The difference maker here is that sodium wants to lose one electron, but the second electron is a core electron.
01:41
So we have a high jump in ionization energy from ie1 to ie2, which makes sodium have the highest second ionization energy.
01:53
Then we want to look for the one that has the smallest atomic radius...