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Consider the equation $x^{4}+c x^{2}+d x-e=0,$ where $c, d$ and $e$ are positive. Show that the equation has one positive root, one negative root, and two nonreal complex roots.

1 positive real root, 1 negative real root, and 2 non-real complex roots

Algebra

Chapter 13

Roots of Polynomial Equations

Section 5

Conjugate Roots and Descartes' Rule of Signs

Polynomials

Rational Functions

Missouri State University

Harvey Mudd College

Idaho State University

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