consider-the-fission-of-uranium-235-a-the-fission-of-uranium-235-begins-with-the-addition-of-a-neu-2

Question

Consider the fission of uranium- 235 .
a. The fission of uranium- 235 begins with the addition of a neutron to the nucleus. What isotope is formed? Give the isotope symbol.
b. After the neutron is added, the uranium atom is more unstable and undergoes fission. A possible set of products is krypton- $94,$ barium- 139 , and 3 neutrons. How many protons are in these products?
c. Were any protons lost?

Marissa Turner · Accepted Answer

this is questioned six from chapter three, Section six and it&#x27;s all about efficient of geranium. 2 35 So the isotope of Iranian looks like this. Who is 2 35 this 1 to 35 over 92 because there&#x27;s 92 pro times in the U for uranium. Okay, when a neutron is added to uranium is can cause nuclear fission, causing a chain of nuclear reactions. And this has come out to form. Barry M. Krypton and Makesem make some new neutron. So these are isotopes that can be formed from it now, Um, Port B is asking how many protons do these isotopes? Half so buryem well still have 56 protons, so very well have 56 and encrypt on the atomic number is 36 so it looks to have 36 regardless of it being an isotope. So what leads to like port? See asking if any protons are lost like no protons are lost during vision like the atomic number. Protons always stay the same for the most part. And it&#x27;s because of this process. Deals more with the neutrons as the reaction will make other Iranian isotopes to undergo fission

Zulfiqar Ali · Answer

when uranium to 38 Ah, uranium to 38 on its atomic number is 92. When this nucleus emits inal elf a particle, the result of nucleus is, uh, it&#x27;s the axe. Its atomic mass decreases by 40 and it&#x27;s therefore atomic masses to 34 and its atomic number decreases by two units and therefore its atomic number is mine t and, uh, similarly, um, we have, uh, plutonium P U. Its atomic masses do 39 atomic number is 94. And when plutonium emits an L for particle, let&#x27;s say the resulting new places acts. Um, it&#x27;s atomic mass decreases by four units. Therefore, its atomic mess becomes 2 35 and its atomic number becomes 92. And, uh, currently, we have ah, tourney. Um, do 29. Its atomic number is 90. Uh, when? Uh, this, um, radioactive element in its, uh a beat a particle. So it emits a beat. A particle then, uh, on atomic mass remains the same, which is 2 39 and atomic number increases by ah one unit. Ah, the airport. Its atomic number becomes 19 1 Let&#x27;s say this is Ah, new piece, eh? This is B, and this one is C. Now let&#x27;s rank them by atomic number. So which has got on the highest atomic number, of course, be has the highest atomic number. And then, ah, comes see, um, so be is greater than say and see is greater than and, uh, by number of neutrons. So by number of neutrons, so by number or neutrons, we have ah, um at first position. See? Well, uh, this new PS uh, the nucleus. See his, um 1 48 Neutrons, This is 1 48 neutrons See has won 48 neutrons and, uh oh, be his 1 43 1 43 new problems. And it is It is 1 44 1 44 neutrons. And therefore so the rank is trust and first position it is. See, c has gone toe the maximum number off neutrons on 48. And then we have a eyes greater than a. And then finally we have b end of the problem. Thank you for watching

Sri Datta Vikas Buchemmavari · Answer

in this reaction, we want to find out how many neutrons are released. And for the second part, we want to find ardently. I doubt the energy released. So first, let&#x27;s count the number off neutrons and protons on both sides. Now the total number of nuclear it&#x27;s on the left side is to 35 plus one, which is to 36 off its 92 our programs. Now on the other side, it is for killing 51 plus 41 which is 92 programs again. And if you consider the total mass number on the left and serve, it&#x27;s 1 33 Listen, 98 which is 100 31 and so 231. So we&#x27;re missing five nuclear arms on we we are. The protons are all accounted for, which means all of these five nuclear arms must be neutrons. And there are five neutrons in this reaction. Five, you transfer released. Now to find the energy released, we&#x27;ll simply find a Cuba you obviously the Cuban you will be the M C squared for reactions minus and Sanskrit for the product. So that&#x27;s mass off to 35 uranium. My less massive neutron minus mass off strip medium. I think my this mask off my you be in, I think minus mass off five neutrons. So that&#x27;s five times the mass of nutrients Times sees Quit August You simply substituting numbers. The massive uranium is to 35.43930 You noticed that there is an M N minus five women giving this minus four women. So that&#x27;s minus four times the mass of neutron, which is 1.866 five. I&#x27;m quite Moskovitz minus a massive stroke medium I wanted to do, or 915250 atomic units minus for niobium. It&#x27;s 97.91 03 to 8 Atomic mass units whiteness and that&#x27;s it finds See squid Notice that I pulled the unit out the atomic march in it. To convert this into elephant, Walter is multiplied by the factor as usual. 9 31.5 Mega electron woods By using square. This factor is equal to one because one uses squared is equal to 91.5 mega combo. This number this whole expression when you plug it in tow. Actuator uses 1 71.1 Mega electron. What&#x27;s as they want of energy released

Eugene Schneider · Answer

So this problem tells us we have uranium two. Thirty five and that we want to write it in the form a Z X and determine how many protons and how many neutrons it has. And so in this form, a Z X is equal to the number of protons, plus the number of neutrons, which is this value right here. This two thirty five that we get from the isotope and Z is equal to the number of protons and sort of write this in this forum we look at the periodic table symbol for uranium is you. We know that it has ninety two protons and that this a value is two thirty five. So to answer the second question, we know we have ninety two protons and we just take two thirty five minus ninety two to find out we have one forty three neutrons

Arron Martel · Answer

one way that a nuclear decay can be induced is by striking an isotope with a free neutron. Now we&#x27;re going to look at one such case where an isotope of uranium 2 35 is struck with a free neutron. When this occurs, the original isotope is split into an adam of Syria, MME. 1 44 and and Adam of Strontium 90. So the question being how many of each type of particle will be produced in this reaction? So if we look this over will notice that if the masses of the products are added up, we get to 34. The original mass presence was a total of 2 36 Therefore, this means that this reaction produced a total of two neutrons. Furthermore, if we check the same principle by atomic numbers and we add up 58 38 we will get 96 and that has a difference of four between the original atomic mass. Therefore, this means that the only way this could be properly counterbalanced would be with four beta particles, so the answer is four beta particles as well as two neutrons

Eugene Schneider · Answer

So this problem tells us that uranium to 35 is used in nuclear fission and wants us to determine the number of protons and the number of neutrons and write it in the form a Z X. And so the number of protons in uranium is always going to be the same. And that is 92 for uranium. You confined that from a periodic table, and then the number of neutrons is going to be this isotope number A minus 92. And so that gives us 143 neutrons now to write it in the A Z X form, this 2 35 is the A, and our Z is the number of protons. So 92 and then X is chemical symbol and for uranium that is you. So this is our ese ex form. And it has 92 protons and 143 neutrons

Problem

Write a paragraph explaining how a nuclear reacto…

Problem 6 Medium Difficulty

Answer

(a) See explanation
(b) See explanation
(c) no protons were lost.

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(a) See explanation(b) See explanation(c) no protons were lost.

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(a) See explanation
(b) See explanation
(c) no protons were lost.

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