Consider the following data for a BOD test. Day DO mg/L 0 9 1 8

Step 1: Calculate the BOD at Day 0 and Day 5. The BOD (Biochemical Oxygen Demand) is calculated

Question

Consider the following data for a BOD test. $$ \begin{array}{ll} \text { Day } & \text { DO mg/L } \\ 0 & 9 \\ 1 & 8 \\ 2 & 7 \\ 3 & 6 \\ 4 & 5 \\ 5 & 4.5 \\ 6 & 4 \end{array} $$ Assume there is no dilution. a. Calculate $\mathrm{BOD}_5$. b. Plot the BOD versus time. c. Suppose you took the sample and after six days aerated it, put it into the incubator, and measured the DO every day for five days. Draw this curve on the graph as a dotted line.

   Consider the following data for a BOD test.
$$
\begin{array}{ll}
\text { Day } & \text { DO mg/L } \\
0 & 9 \\
1 & 8 \\
2 & 7 \\
3 & 6 \\
4 & 5 \\
5 & 4.5 \\
6 & 4
\end{array}
$$
Assume there is no dilution.
a. Calculate $\mathrm{BOD}_5$.
b. Plot the BOD versus time.
c. Suppose you took the sample and after six days aerated it, put it into the incubator, and measured the DO every day for five days. Draw this curve on the graph as a dotted line.

Introduction to Environmental Engineering

P. Aarne Vesilind,… 3rd Edition

Chapter 9, Problem 16

Instant Answer

Step 1

The BOD (Biochemical Oxygen Demand) is calculated as the difference in dissolved oxygen (DO) between Day 0 and Day 5. \[ \text{BOD}_5 = \text{DO at Day 0} - \text{DO at Day 5} \] \[ \text{BOD}_5 = 9 \, \text{mg/L} - 4.5 \, \text{mg/L} = 4.5 \, \text{mg/L} \] Show more…

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Consider the following data for a BOD test. $$ \begin{array}{ll} \text { Day } & \text { DO mg/L } \\ 0 & 9 \\ 1 & 8 \\ 2 & 7 \\ 3 & 6 \\ 4 & 5 \\ 5 & 4.5 \\ 6 & 4 \end{array} $$ Assume there is no dilution. a. Calculate $\mathrm{BOD}_5$. b. Plot the BOD versus time. c. Suppose you took the sample and after six days aerated it, put it into the incubator, and measured the DO every day for five days. Draw this curve on the graph as a dotted line.

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