00:01
Given this function f, we have asked to do these four things here.
00:06
Let's start work the first thing.
00:11
So we're supposed to compete the gradient of f at this point p plus define the gradient of f.
00:20
So we have e raised x, y, z, minus one.
00:26
So we're going to use the chain rule.
00:29
So e to x, y, z.
00:33
So we're going to bring it y z out here.
00:35
We have e to x, y, z minus 1.
00:40
And we do the same thing with respect to y and z.
00:45
So for y, we get xz times e to x, y, z minus 1.
00:55
And for z, we get x, y, times e to the x, y, z minus 1.
01:02
Now let's plug in the values for p...