00:01
We're as to find a connected weighted simple graph with the fewest edges possible that has more than one minimum spanning tree.
00:15
So we have that if the graph is simple and connected and has more than one minimum spanning tree, then of course the graph cannot, i guess i should say the weighted graph.
01:09
Simple and connected it has more than one minimum spanning tree, then the graph cannot be a tree itself.
01:18
Otherwise, we would only have one minimum spanning tree, which is the graph itself.
01:24
And since a graph on n vertices, or i guess i should say a tree on n vertices has exactly, n minus 1 edges, it follows that the weighted graph should have at least as many edges as vertices.
02:20
So for this problem, there are many different, infinitely different graphs we could pick.
02:30
That would be a solution.
02:30
For the simplest examples, suppose that the graph has three vertices.
02:40
Let's try and find a graph that has three edges.
02:46
If we can do this, then it follows that this graph has the minimum number of edges and still has more than one's name of tree.
02:57
Because if we only add two edges, then we have a tree already.
03:02
So consider if we have a graph with vertices.
03:08
A, b, and c, and because we have three edges, we obtain a cycle.
03:20
And let's label the rated graph so that each edge has the same weight.
03:31
So 1, 1, and 1.
03:38
Well, then it follows that for this graph, the graph with edges ab and b is the minimum spanning tree, as well as the graph with edges ab and ac, as well as the graph ac and bc.
04:25
So these three graphs are all minimum spanning trees...