For nitric acid, the reaction is:
$\mathrm{Pt}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Pt}$ with $\mathscr{E}^{\circ}=1.188 \mathrm{V}$
For hydrochloric acid, the reaction is:
$\mathrm{PtCl}_{4}^{2-}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Pt}+4
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