00:02
Continuing on with electrochemistry, we're essentially looking at how electrons move throughout our system.
00:06
So we have several different electrode reactions.
00:09
So the first, where we have irc -l -63 minus, have an e value of 0 .77, p -t -c -l -2 minus, 0 .73 volts, pdcl -42 minus, 0 .73 volts, pdcl -42 minus, 0 .73 volts, pdcl 42 minus, 0 .6.
00:34
6, 2 volts, where we add a series of electrons, add 3 electrons, and 2 electrons, with 2 electrons to generate our products.
00:46
So we can use our nuanced equation here to determine the e -cell for all 3 metals at specific concentrations, where the e -cell equals e0, subtract 0 .0 .0592, divided by n, multiplied by log of the q, where q is essentially the concentration of the products divided by the concentration of our reactants.
01:15
So for the first example, we'll do it in 4 foot erredium metal with the concentration of 0 .02 molars.
01:22
We have e -cell equal to e0, subtract 0 .05592 divided by n, log of ir, multiplied by cl minus to the power 6 because of the stochymetric coefficients.
01:38
Irc .l63 minus.
01:41
We get a value of 0 .74.
01:44
When we plug in 3 molar here and 0 .77 volts here.
01:55
That's for the first one.
01:57
We then have the second and the third...