00:01
So these are two reactions we're given.
00:02
And in order to get all the information we need, i had to look up what their standard cell potentials are.
00:08
And i got 1 .49 and 0 .96.
00:11
So now we have all the information we need to solve this problem.
00:14
We're asked to think, well, would n03 minus be able to oxidize mn2 plus? now, both of these reactions are written in the form of a reduction.
00:25
Remember, a reduction means we're gaining electrons.
00:29
And so in both these cases, we're like saying there's going to be electrons on the reactants and so like we're going to be gaining.
00:39
And so that's not, we need to split one of the reactions around because we always have one reduction and one oxidation.
00:45
Now, we're told the no3 minus is going to oxidize the mn2 plus.
00:50
So we need this to be the reducing equation where if no3 minus is oxidizing something else, it itself is going to get reduced.
00:59
So this is correct.
01:00
But we need to flip this reaction, the one up here, to make it an oxidizing reaction...