00:01
For question 25, we're asked to consider the following hypotheses.
00:04
So the no hypothesis is population mean is greater than or equal to 45.
00:10
And the alternative hypothesis is that new is less than 45.
00:16
And we're also told that we're dealing with samples of size 36 and that the confidence level for the question is alpha equals 0 .01.
00:29
Now, so then we have part a, part b, and part c.
00:32
In each of these parts, we're given a sample, and we're asked to calculate the p value and draw any conclusions with regard to our hypotheses.
00:40
So one thing to consider is that this is a one -sided test.
00:48
In particular, it's a lower -tail test.
00:55
And the reason that it's a lower -tail test is because the alternative hypothesis is mu is less than 45, so that's less than the no hypothesis.
01:08
And part a, we're given a sample average of 44 and a sample standard deviation of 5 .5.
01:18
And so the test statistic in this case is we don't have the population standard deviation.
01:26
So sample averages are distributed according to the t distribution.
01:30
So we're using the t test statistic.
01:34
And that is equal to the sample average minus population average divided by the sample standard deviation over the square root of the sample size.
01:44
And so for part a, this is 44 minus 45 over 5 .2.
01:53
Divided about square root of 36.
01:56
And this comes out to minus 1 .152.
02:01
And now we can use the t table to look up our p value.
02:05
But just a quick comment on this.
02:08
So suppose our symmetrical t distribution looks like this.
02:15
And normally when we look up the t value in the t table, it's giving us an area that is, it's giving us an upper -tailed area.
02:24
So it's all the area in the distribution above our t score.
02:28
But here we have a minus t score.
02:33
Let's say this is plus 1 .152.
02:37
So we're actually interested in the lower tailed area.
02:40
But due to symmetry, we can say that the area in this tail is identical to the area in this tail.
02:47
So we can treat it as if our t score is positive 1 .152 and then just take the upper -tailed area that's given in the table directly from the table.
03:02
I'll just delete this before moving on.
03:12
Okay, and then one more point to make is degrees of freedom is equal to n minus 1, which gives us 35...