00:01
Hello, so here we have our hypotheses as the null hypothesis is going to be mu is greater than equal to 10, and then our alternative hypothesis is going to be mu is less than 10.
00:10
So here we have our sample n is equal to 120, and our standard deviation, sigma, is 5, with alpha equal to 0 .05.
00:20
So our test statistic is then equal to x bar minus mu not.
00:24
So that's going to be x bar minus 10 divided by sigma, so 5 divided by the square root of 120.
00:35
And based on the critical value approach, we get that z sub 0 .05 is equal to 1 .645.
00:44
So the rejection rule for the lower tail is that we reject h not if z is less than or equal to negative 1 .640.
00:55
5.
00:56
So here we get that z is going to be equal to, again, we found right here.
01:02
Solving for x bar, we get that x bar is going to be equal to, well, x bar is less than 10 minus 1 .645 times 5 over square root of 120, which is going to be equal to 9 .25.
01:20
So therefore we reject h0 whenever x bar is less than or equal to 9 .25.
01:26
This means that we made the conclusion to not reject h0 whenever x bar is greater than 9 .25.
01:35
So we take the population mean here, mu to be 9.
01:39
And if mu 9 is really true, then the probability of accepting h0 when mu is greater than equal to 10 is equal to the probability.
01:50
That the sample mean x bar is greater than 9 .25 when mu is equal to 9...