00:01
Now, on this problem, we want to find the marginal distributions, given the joint probability distribution here.
00:07
Now, in order to find the marginal distributions, we need to integrate out the other variable.
00:13
And so, if x, if x, means we integrate out the y.
00:18
And so we integrate from 0 to 1, 3x minus y over 11, d .y.
00:27
And so this gives us 1 .11 times 3xy minus 1.
00:34
Evaluated from y is 0 to 1, plug in 1, plug in 0 for y, and then subtract.
00:45
And this gives us 1 .11 times 3x minus 1 1 1 1ā2 is our f of x.
00:53
Now similarly for f sub y of y, we integrate out for x.
01:04
And so this is 1 11 times 3 halves x squared minus x y, evaluated from x equals 1 to 3.
01:17
And so now for x, we're going to plug in 1.
01:20
We're going to plug in 3, and then we're going to subtract them.
01:25
And whenever we do, this gives us 1 .11 times 12 minus 2 y...