00:02
Question 72 is a mechanism question where you are asked to derive the rate law based upon the mechanism that is provided.
00:13
It is for an enzyme catalyzed reaction, a generic one where we have e representing the enzyme, s representing the substrate, and then our product becoming es in the first step.
00:28
We know that this is fast and reversible because they give us.
00:32
The arrows in both directions, so we can write a rate law for the forward direction, which will be k1, multiplied by the concentration of e, multiplied by the concentration of s.
00:46
But because it's reversible, we can also write a rate law for the reverse reaction, which will be equal to k minus 1, multiplied by in the reverse direction, es is the reactant, so the es concentration.
01:01
Because this is a elementary reaction, then the coefficients, which are all one, determine the order with respect to each reactant.
01:11
The second step has a k2 rate constant, and it takes the intermediate es and recreates the enzyme plus our product that we call p...