0:00
Hello there.
00:01
So for this exercise we have these two systems of these two linear systems.
00:08
But basically you can observe this corresponds to the homogeneous system and this to the non -omogeneous system.
00:16
So then the first part we need to find the general solution for the homogeneous system.
00:23
So let's represent this as an stem matrix.
00:27
So that means taking these matrix here 0, 0 .0.
00:40
Okay, but look, we have something happen here.
00:44
The third row is equals to minus the first row.
00:49
And the second row is two times the first row.
00:53
So technically these two rows will eliminate by doing the following operations, row operations.
01:00
So if we take r2 and then we say that our 2 minus 2 times r1, and r3 will be r3 plus r1.
01:13
So by doing those operations, we obtain the following.
01:20
So we just let me copy this and i would write everything.
01:25
So these two rows will become zeros.
01:29
0, 0, 0, 0, 0, 0.
01:31
So we need to find this solution for this system.
01:35
You can see by the matrix that we have only 1 pivots...