Question

Consider the following pseudo-code. Assume that IntQueue is an integer queue. What does the function fun do? ``` void fun (int n) f IntQueve q = new IntQueue(); q.enqueue (0); q.enqueue (1); for (int i = 0; i<n; i++) i int a = q.dequeue(); int b - q.dequeue(); q. enqueue (b); q.enqueue (a + b); print(a); } l ``` A. Prints numbers from 0 to $\mathrm{n}-1$ B. Prints numbers from $\mathrm{n}-1$ to 0 C. Prints first $\mathbf{n}$ Fibonacci numbers D. Prints first n Fibonacci numbers in reverse order.

   Consider the following pseudo-code. Assume that IntQueue is an integer queue. What does the function fun do?
```
void fun (int n)
f
    IntQueve q = new IntQueue();
    q.enqueue (0);
    q.enqueue (1);
    for (int i = 0; i<n; i++)
    i
        int a = q.dequeue();
        int b - q.dequeue();
        q. enqueue (b);
        q.enqueue (a + b);
        print(a);
    }
l
```
A. Prints numbers from 0 to $\mathrm{n}-1$
B. Prints numbers from $\mathrm{n}-1$ to 0
C. Prints first $\mathbf{n}$ Fibonacci numbers
D. Prints first n Fibonacci numbers in reverse order.

Data Structures Using C

Amol M. Jagtap, Ajit… 1st Edition

Chapter 2, Problem 31

Instant Answer

Step 1

Step 2: The function starts by creating a new integer queue `q` and enqueuing two values: - `q.enqueue(0)` - adds 0 to the queue - `q.enqueue(1)` - adds 1 to the queue So initially, the queue contains [0, 1]. Step 3: Then it enters a loop that runs `n` times Show more…

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Consider the following pseudo-code. Assume that IntQueue is an integer queue. What does the function fun do? ``` void fun (int n) f IntQueve q = new IntQueue(); q.enqueue (0); q.enqueue (1); for (int i = 0; i<n; i++) i int a = q.dequeue(); int b - q.dequeue(); q. enqueue (b); q.enqueue (a + b); print(a); } l ``` A. Prints numbers from 0 to $\mathrm{n}-1$ B. Prints numbers from $\mathrm{n}-1$ to 0 C. Prints first $\mathbf{n}$ Fibonacci numbers D. Prints first n Fibonacci numbers in reverse order.

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