00:01
This question has a bunch of different reactions in it.
00:03
And so part a says when c5h12 is reacted with cl2 and the presence of uv light, four different monoclorination products form.
00:11
And they ask what the structure of c5h12 is.
00:14
So in order for four different monoclorination products to form, we need four unique carbons.
00:20
So we can do that on c5h12 by doing this.
00:29
So here we have five carbons and 12 hydrogens, but only four.
00:33
Unique hydrogens.
00:35
So these two are the same.
00:37
And then we have this one is unique, this one is unique, and this one is unique.
00:45
So four possible products, because we have four unique spots to put the chlorine.
00:50
Part b says that when c4h8 is reacted with water, a tertiary alcohol is produced as the major product.
00:57
What is the structure of the c4h8? so if we're reacting with water.
01:02
That means to get an alcohol, that means that we're going to be an alken.
01:05
And if we want a tertiary alcohol, we just need one carbon to be tertiary.
01:09
So we can do something like this.
01:16
So this is an alken.
01:17
If we react it with water, this carbon will get the alcohol and that will be a tertiary alcohol since that carbon is connected to three other carbons.
01:25
Part c says when c7h12 is reacted with hcl, one chloro, one methyl cyclohexane is produced as the major product, what are the two possible structures for c -12, c -7 -h -12 in this reaction? so first i want to draw the product.
01:41
The product is one -chloro, one methyl, cyclohexane.
01:44
So cyclohexane, one chloro -one, one methyl...