00:01
This question belongs to the laws of thermodynamics in which we have a four -step process and for the part a, we have to calculate the work done in each step.
00:08
So, work done in, uh, work done in, uh, wogden is given by minus p multiplied by delta v or delta v can be written as v final minus v initial.
00:19
So now for the process ab, so work done a b, this can be written as and the for the a b, the pressure is minus pressure is 300 kilo -pascals, so 10 to the power 3 and v final it is at the b point so it is 4 meter cube and v initial it is 1 meter cube so from here after solving we get work done in process a b this is equals to minus 9 .0 multiplied by 10 to the power 5 jule and now for the process b c the volume is constant so work done will be 0 okay because change in volume is here 0 now for the process cd so cd process the so, work done is minus and pressure is here 100 kilo pascal.
01:01
So 100 into 10 to the power 3.
01:03
And v final is of the volume at the d.
01:06
So volume at the d is 1 meter cube.
01:09
And volume at the c, it is 4 meter cube.
01:11
So from here after solving, we get work done for the process cd.
01:15
It is equals to plus 3 .0 multiplied by 10 to the power 5 jule...