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Consider the $\frac{65}{29} \mathrm{Cu}$ nucleus. Find approximate values for its (a) radius, (b) volume, and (c) density.

(a) $4.82 \mathrm{fm} .$

(b) 470.48 $\mathrm{fm}^{3}$

(c) $2.313 \times 10^{17} \mathrm{kg} / \mathrm{m}^{3}$

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Okay, So first we're looking for the radius of this copper nuclear's. We're going to use the equation. R equals constant. A times the mass number. So the one dirt power, our constant A is 1.2 times 10 to the negative 15. And our mass number is the number of protons and neurons for this nucleus we see here that is 65 raised to the 1/3 power. You know, this is meters. It's constant A. And for an answer, we get 4.82 times 10 to the negative 15 meters or is can be expressed as four point a so centimeters. Next. You want to look for the volume, find volume it ISS for third time. Spy really is killed. We already saw for the radius appear so once we plug that in, we will get an answer off 4.70 times 10 to the negative 43 meters. Lastly, we're looking for the density Density is mass over volume. Now for this nucleus, we need to find the total mass. The total mass would be the massive one proton or neuron. Since they're about the same weight times, the number of protons and neutrons, which is our mass number over the volume which we saw before. So the mess of one proton or neutron is 1.67 times 10 to the negative 27 kilograms. We have 65 of these mass number all over of Are you much we previous myself 4.70 times 10 to the negative for the okay, this is mirror so cute. I forget the units. So that gives us some density off 2.31 sounds turn to the 17 kilograms over meters Cute.

University of Massachusetts Amherst