00:01
In this problem, we have three things to do.
00:03
We have to consider this cell.
00:05
And the first thing we're going to do is figure out our e cell.
00:08
So let's write our cell reaction.
00:14
And my cell reaction will be, so i have my gold plus my thallium and then my gold plus my, i will have three here.
00:54
Here and my this will be equal 1 .50 volts plus 0 .34 volts.
01:09
It'll be 1 .84 volts.
01:15
So for my e for my cell, we'll be looking at 1 .84 volts.
01:24
Second thing we're asked to do is find delta g and k.
01:28
Okay, first delta g.
01:42
Delta g will equal negative n equal to l.
01:52
So this will be equal to n is equal to 3 moles of electrons, which we just saw times 96485 c over moles of electrons times 1 .84 j over c times 1000 1000 joules per kilojoule.
02:33
This will equal, let me find my calculator.
02:38
Oh, i need to get a negative there.
02:40
Negative 3 times 96 or 85 times 1 .84 divided by 1000.
02:48
This will be negative 532 .6.
02:54
So this will equal our delta g will equal to 3 sig figs 533 kilojoules.
03:09
Okay so my k, what am i supposed to find here, and k will be equal to 10 to the 3 times 1 .84 divided by 0 .0592.
03:48
My k will be equal to second log to the 3 times 1 .84 divided by 0 .0592 is 1 .75 times 10 to the 93.
04:12
Okay, hang on a moment.
04:23
The text actually says it's 2 .52 times 10 to the 93.
04:35
Let's try this.
04:38
I am, i got to go verify what my temperature is.
04:45
25.
05:12
Let me try one more thing here.
05:56
I'm getting that.
05:57
1 .75 times 10 to the 93rd...