00:01
There are four ionic compounds, kf, n -s -e -l, n -a -b -r, and lithium chloride.
00:05
We have to use ionic radii from figure 7 .8 to estimate the cat -ion -an -ion distance for each compound, and then based on that distance, we have to arrange these four compounds in order of decreasing lattice energy.
00:22
Then we have to check our predictions in part b with the experimental value of lattice energy from table 8 .1 and are the predictions from ionic radia correct or incorrect we have to explain that first let me find the catarine anion distance from the data in figure 7 .8 for k a plus ionic radius is 152 p .m and fluoride minus is 100.
01:00
19 p .m.
01:02
Picometer.
01:03
So it is 271 picometer.
01:08
For any cl, any plus ion is 116 p .m.
01:14
Plus cl minus ion 167 p .m.
01:20
Together it is 283 p .m.
01:24
Cation anion.
01:25
Distance.
01:25
For any br, sodium ion, 116 p .m.
01:33
Plus 182 p .m.
01:36
For the anicadi of bromine.
01:41
So in case of nabr cat aneur dstan anand distance is 298 p .m.
01:49
And for lithium chloride, for lithium iron, it is 90 piquometer.
01:56
And for 167 picometer.
02:04
So it is 257 picometer.
02:11
So you can see here the highest distance is for sodium bromide and least catalanine distance is for lithium chloride.
02:24
Okay now we have to arrange these four compounds in order of decreasing lattice energy...