00:01
Okay, this question asks us about a parallelogram where we have one of its sides equal to u, and then the adjacent side equal to v.
00:15
So then filling in the rest of the parallelogram, this side would be minus u, and this side would be minus v.
00:27
And it asks us about the diagonals of this shape.
00:31
So for the first diagonal, this one's pretty easy to see because we just go.
00:36
Go u to the right, then v up to make that.
00:40
So this is u plus v.
00:48
And then our other diagonal going here, we see we go u to the right, but then v down.
00:58
So this is u minus v.
01:05
So now that we found this, we have to show that the diagonals have the same length if and only if u .d .v equals zero.
01:17
So the length of the first diagonal is just the magnitude of u plus v or l1 squared is equal to the magnitude of u plus v squared and i wrote it like that because we can write this now in terms of a dot product which we know using foil this evaluates to magnitude of u squared plus the magnitude of v squared plus two times the the dot product of u and v.
02:04
So that's our length of the first diagonal and then we'll do the same thing for the second, which is the magnitude of u minus v, and we'll talk about the square.
02:19
So this gives magnitude of u plus magnitude of v squared each minus two times u.
02:33
And we see here l1 has a plus 2 u .dv and then l2 has a minus 2 u .dv and they're only going to be the same if u .dv equals 0.
02:55
So that's the first part and then we have to prove it going the other way...