The magnitude of a vector is given by the formula $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$. Here, $x_1 = 2$, $y_1 = -4$, $x_2 = 2$, and $y_2 = 1$. So, the magnitude of $\overrightarrow{AB}$ is $\sqrt{(2-2)^2 + (1-(-4))^2} = \sqrt{0 + 25} = \sqrt{25} = 5$.
So,
Show more…