consider-the-points-in-exercise-5-in-section-81-which-of-mathbfp_1-mathbfp_2-and-mathbfp_3-are-in-co

Name: consider the points in exercise 5 in section 81 which of mathbfp_1 mathbfp_2 and mathbfp_3 are in co
Uploaded: 2021-01-02
Duration: 5 min
Channel: Numerade
Description: Consider the points in Exercise 5 in Section $8.1 .$ Which of $\mathbf{p}_{1}, \mathbf{p}_{2},$ and $\mathbf{p}_{3}$ are in conv $S ?$

Question

Consider the points in Exercise 5 in Section $8.1 .$ Which of $\mathbf{p}_{1}, \mathbf{p}_{2},$ and $\mathbf{p}_{3}$ are in conv $S ?$

Lucía Guerrero · Accepted Answer

one way we can use to say if the peace are in the complex, how off s is finding its very central coordinates on that requires to solve the following equation for each eye to solve P I minus v I it goes quiet efficiency, I time speak to minus 31 plus a coefficient C three times speed three minus B one on. Do we have to find the code efficiency one and C three on board? We can do that by reducing the following augmented matrix. So the first column is gonna be be to minus B one the second column, B three minus B one, which is zero minus 60 then p one minus p one p two minus be one on finally be three minus b one. Now if we multiply the 1st and 2nd rose by minus one on if we add yes. So if we multiply the first row by minus one on the first row by minus one we obtained yes, and then we add minus three times the first wrote Third road on We obtained cereal, cereal, civil, my understand in Syria. So from here we can see that in the column corresponding to P two. There&#x27;s a minus stand at the bottom, which makes the system inconsistent. Eso there is no solution for us. You want to see three when we consider the victory p two on from here? Well, we can conclude that p two does not belong to the convicts. Whole off s Andi. If we ignore this column on we keep producing that ISS. If we subtract the first road the second road we obtained 10 minus one minus four to Oh, sorry, we&#x27;re going Thio, ignore this second column on, uh 06 minutes 60 and will the last room 00 Um then we divide by six. We obtained 10 minus 12 on 01 minus 10 Syria 000 on from here. Well, we can write that my news be to minus B one minus again, be three minus. B one is equal to P one, minus b one on. If we rewrite this, we have three b one minus speak to minus B three calls p one on. In this linear combination, there are coefficients which are negative on DSO. We conclude that p one is not in the complex. Whole off s on from the last column, which corresponded to P three. We have the following, so we have two times with two minus V one equals p three minus Big one on this can be written us to be to minus 31 It goes to be three on board again. From here we see that the second coefficient is negative. So Petrie is not in the comics haul off s. So in this exercise, none of the peace belonged to the complex Whole off s.

Gideon Idumah · Answer

solve this problem with constructs. The Matrix be won&#x27;t beat so b three p one pizza Ooh p three should go about to exercise six in section It&#x27;s points warn Be one is giving us 211 beats wants 10 minus two. Beatty was to minus 51 and they have your P wants to be zero minus night scene minus five, 1.5 minus 1.3 minor, 0.5 and they are five minus four on zero. So we&#x27;re reduced. These so reduce and they have warned 00010 001 minus for 23 zero point Sue 0.50 point 31 Juan Juan Non notes or recorder. This is pew on. This has been so this is speed three. So that means we have. That&#x27;s p one would be minus for V one. Lost. So v two blustery V three. Andi Um, some of the professions some of coefficients is minus for close to blustery, which is one boards p one, as in negative, quick, efficient CE, which is the minus four. That&#x27;s his minus four. So this implies that p one he&#x27;s not in the convicts All off s. You call that it&#x27;s most B. It&#x27;s almost off positive coefficients. So now let&#x27;s look at pizza. We have pizza equal to zero point. Sue V one lost 0.5. It&#x27;s who lost 0.3 v three. If you look at it, some off coefficient of these you have that This is zero point Sue blow 0.5 blow Zubrin theory, which is a costa one pew worn or pizza as and force. It&#x27;s Eve coefficients. So this implies that pizza Ooh is in the convicts all off x now. Lastly, we have p three. You called so V Juan loss. Vivid Sue Philosophy three. And then we are that this some off the coefficients is one loss, one loss warn, which is a go to three on DNA. Now we see that this because it&#x27;s not quarts of one, it&#x27;s implies that victory is not in the convicts all off, So only pizza Ooh, is in the convicts. Call off this

Vikash Ranjan · Answer

in the ocean. You define the company off pick you Therefore, even as you went toe complimented his X and y So it is two minus three on DDE seven minus two. This is equal to minus violent five. This is a component off. Be correct. Did answer doing problem?

Brandon Fox · Answer

So let&#x27;s use the foil method. The first R three p times two p, which is six p then we have a three p times. This is the outside three feet, times a minus 5/3 que which is gonna be, um, a minus five p. Q. Now let&#x27;s do a five force Q times of two p, which is going to be a plus five halves p que and then our our last, which in this case will be a minus 25 12th Q squared. Actually, this 1st 6 p should be six p squared. Now let&#x27;s combine the two middle term So we got the six p squared. Now we have our negative five. Plus, our five have negative five plus five halves and we get negative 2.5 So negative 2.5 p que and then R minus 25 12. Hughes squared

Vikash Ranjan · Answer

director Br just given us minus two on seven. So we are is given as minus two minus X. I got last seven minus lying in a cab because we have assumed the point. Be as thanks I got less right Dig. Get so the B are given as minus two. I last seven j Jack, Just give it as miles doing minor sex. I don&#x27;t last seven minus y j caf. So we will agree. This left inside a night inside the coffee&#x27;s himself I am J will have 10 minus two equals minus two minus six their food ministry cancer This banister becomes X equals judo Andi, we have seven girls in seven miners Survived the seven gather this Simon becomes we have one glass judo Therefore we have the point be as geo and deal Therefore the back to be is given as do I last day today This is dancer to live in problem

Brandon Fox · Answer

So let&#x27;s start by multiplying this three p cubed into the to P squared, which is a six p to the fifth and also into here, which is a plus 15 p to the fourth. Okay, and now let&#x27;s go ahead and multiply these Ah, binomial and trying to only altogether. Let&#x27;s start with the six p to the fifth time&#x27;s the first term P cubes. So six Peter the eighth. Now multiply it by the two piece O plus 12 Peter the six and by the one so plus six p to the fifth. Now let&#x27;s do the ah, the 15 p of the fourth times by the P Cube. So plus 15 p to the seventh by the to P would be plus 30 Peter the fifth and then by the ah. By the last term, there will be a plus ah, 15 p to the fourth power. We really only have one to light terms there. So let&#x27;s re write this six p 88 plus 12. Peter, the six add 36 30 together to get plus 36 p to the fifth. Check it out here. Oh, I forgot the Peter the seven. That&#x27;s what I&#x27;m missing. I knew I missed something here. Let&#x27;s go back here. Six p the eighth plus. And we have the 15 p to the seventh power. There we go. Now we have the peace of the six. Power plus 12 Peter the six. And now plus the 36 p to the fifth. Yep. And then the plus 15 p to the fourth of the M there.

Problem

Consider the points in Exercise 6 in Section $8.1…

Problem 3 Easy Difficulty

Consider the points in Exercise 5 in Section $8.1 .$ Which of $\mathbf{p}_{1}, \mathbf{p}_{2},$ and $\mathbf{p}_{3}$ are in conv $S ?$

Answer

None of these.

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Linear Algebra and Its Applications

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David C. Lay, Steven R. Lay, Judi J. McDonaldLinear Algebra and Its Applications

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David C. Lay, Steven R. Lay, Judi J. McDonald

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