00:01
So here, we're given this reaction of hcl and barium hydroxide.
00:03
It's 2hcl plus barium hydroxide will form some products.
00:12
Actually, doesn't matter here.
00:13
But most importantly, it's going to give off 118 kilojoules per mole of reaction.
00:19
And so i'm going to make a quick point here.
00:22
That's going to be very important later on.
00:23
This is per mole of reaction, which is to say, for every 2 moles of hcl that we have react, we're only getting 118 kilojoules per mole.
00:32
So don't mix that up.
00:34
We'll need that information later.
00:35
And so the basic premise of this problem is that we have a certain amount of hcl and baryan hydroxide react.
00:43
We need to figure that amount out so that from that amount we can figure out how much heat is released.
00:49
And then using that the amount of heat is released, we're going to use that as q, which equal to mc delta t for the solution outside of basically the solution.
00:59
That the reaction is taking place and you can still do this calculation we're going to know q we know the mass we know this specific heat we'll find the change in temperature so first step is really stoichiometry figuring out the limiting reagent and so i'm going to erase this our first step is to figure out which of these two reagents do we have less of or which one's going to be the limiting one so for our hcl you have a point one liter hundred mil liters but just dividing right away times 0 .5 molar solution but that's moles per liter remember and so our leaders units cancel out we have 0 .05 moles of hcl for the barium hydroxide we have 0 .3 liters times 0 .1 mole per liter so our leaders units cancel out and we find that we have 0 .03 moles of barium hydroxide but here's you have to be careful.
02:05
You might think, oh, well, we have less barium hydroxide.
02:08
That's our limiting reagent.
02:10
Not exactly.
02:11
Because look at the psycheometry.
02:13
For every mole of reaction of barium hydroxide, we would need two moles of hcl.
02:18
And so to react at this 0 .03 moles of barium hydroxide, we would need twice as many moles with that of hcl.
02:24
That would be 0 .06...