00:01
So continuing on with some work based on thermodynamics, the first step we have here is to calculate our delta g0 value.
00:07
Delta g0 is equal to delta g0 f of n204, subtract two times delta g naught fno2.
00:19
Both of those are gases.
00:23
So what we get is a value delta g0 is equal to negative 6 kilojoules per mole, to minus 1.
00:31
And then we can put our temperature into kelvin.
00:33
So t in kelvin is equal to 298 .15 kelvin.
00:41
So now we can look at the first part, that is part a.
00:46
So our reaction quotient, q, is equal to pn204, divided by pn02 squared.
00:57
That is equal to 1.
00:59
So we can plug our numbers into the following equation.
01:06
Delta g is equal to delta g not.
01:09
Add our tlnq, where delta g is equal to negative 6 kilojoules per mole.
01:18
So the value of our delta g here is negative, so this means that the free energy, our product, is less than the free energy of its reactants...