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Consider the reaction$$2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g)$$At $430^{\circ} \mathrm{C},$ an equilibrium mixture consists of 0.020 mole of $\mathrm{O}_{2}, 0.040$ mole of $\mathrm{NO},$ and $0.96 \mathrm{mole}$ of $\mathrm{NO}_{2}$. Calculate $K_{P}$ for the reaction, given that the total pressure is 0.20 atm.

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$$K_{p}=1.5 \times 10^{5}$$

Chemistry 102

Chapter 14

Chemical Equilibrium

Carleton College

Brown University

University of Toronto

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

02:53

Consider the following rea…

05:24

At $2200^{\circ} \mathrm{C…

02:52

01:21

05:14

Consider the reaction:…

03:00

So we want to find the KP value or the equilibrium constant taking to account partial pressure for this balance scientific equation. So, looking first at what finding KP is going to mean we're gonna do partial pressure of our product. Priest, how many moles we have over partial pressure of our first reactant race? How many moles we have multiplied by our second reacted. And since we only have a understood one here, this is just raised for power of one. Anything race that power one is just itself. But in order to calculate the KP value, we have to know what the partial pressures of these different substances actually are. And to do so, we're going to use falling equation, which is the ideal gas equation. But we're going to rearrange it so that we're finding partial pressure and we are given our mole values, which is this end in the problem itself. Are is a constant that we know is the ideal gas constant and temperature. We were told waas 430 degrees Celsius, which is equivalent to 703 degrees. Kalfin, if you were to do the full conversion of the units So in order to find the parts of pressure, we want to know what the partial pressure is of each of thes. So let's first start with our products. So we know that the pressure it's going to be equivalent to the number moles which were given as 0.96 It's ideal gas, constant times, absolute temperature, all of the volume. Looking at our first reactive, which is in o, you can see pressure is going to be equal to you were told the moles What's your 0.4 hice Ideal gas, close ties temperature all over the value For then lastly, being in our last reacted auction you pressure you're told that we have 0.2 moles turns the ideal gas costs it times temperature all over the volume. So now that we have the very equations for each of the substances we were told, and the problem that the total gas was zero point to a t. M. So since we know this value were able to add together all of the different parts since we know all of these added up to the total gas value that we were given, so we can simplify this. As I said earlier, because we know most of these values and we're looking to find with the volume is because we were not given the volume. We can simply dio the addition. Um, all the moral values and these were gonna be multiplied by our TV sets 0.0 8 to 1, which is our ideal gas constant times the absolute temperature value in Calvin that we calculated here and all of this. Let's make this Louis traitor. All of this is divided by V, so that volume is equivalent to 200 in 94 leaders after this all calculated out. So now that we know these values were able to see what it would be if we were to plug them into here. So our numerator it's going to be 0.96 are tee over the volume raised to the second power. All this going to do 0.4 our teeth. Overbey, I need this. Then 0.2 are tee over the volume. We are able to do some supplication here and here so we can see that this becomes to your 0.96 squared over 0.4 squared. And then we know all parts of this of the equation now and we know that that be value that we found the volume here to be 294 leaders. So if you calculate this out completely, you get that. The KP value is equivalent to 1.5 times 10 to the fifth.

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