00:01
So for this problem, we're given the reaction of calcium carbonate, c .a .c .o .3, as a solid, decomposing to calcium oxide and carbon dioxide as a gas.
00:20
And what they want us to do is calculate delta g, not, or at least predict it, at varying temperatures, at 298, 1055, and 1455 kelvin.
00:38
And so to do that, we first need to calculate, well, think back to this formula.
00:43
Delta g equals delta h minus t delta s.
00:49
So we need to go back and find out what delta h delta s are.
00:54
And so we can find those out by doing this, or delta h equals h not of products minus the enthalpy formation of the reactants.
01:12
And normally you have to account for the stoichiometry.
01:15
But it's all one to one, so there's no molar coefficients you need to consider.
01:20
So you can find these numbers.
01:22
Same thing for delta s.
01:27
And so you can find these values in your textbook and an appendix.
01:32
And so i've already looked them up.
01:34
So delta h not equals negative 634 .9 minus 393.
01:46
0 .5.
01:47
So these are your products minus your reactant, which is negative 1 -207 .6 so that gets you 179 .2 kilojoules.
02:01
Delta s can be found similarly, delta s -0...