00:01
In this question we've been given some data and we've been asked to determine the standard enthalpy change of the reaction and the standard entropy change of that reaction.
00:15
So when we look at entropy as a definition, this is just the disorderness, the measure of the disorderness of a system.
00:23
And in terms of thermodynamics, this will be the amount of thermal energy possessed by a system that is actually available to do work.
00:31
So if we look at the data that we've been given, we can tell that if we have for example lean k being equal to negative delta the standard enthalpy change of the reaction divided by r multiplied by 1 over t plus the standard entropy change of that reaction divided by r so if we plot our lean k against 1 over t we're going to have this being equal to the gradient this part being equal to the gradient and this being equal to the gradient to the y intercept.
01:09
This is the form of y is equal to mx plus c.
01:14
Where our m is the gradient which is in this case is this expression right here and our c is the y intercept which is this expression right here.
01:24
This is a linear equation.
01:26
So if we plot our values, plot these on a curve, we are going to have something like this is link k against 1 over t so we are going to have a straight line graph that looks like something like this so all we need here we need this expression and what we are going to get here is y is equal to negative 6 because remember we just want the cladent and the gradient is the changing y over the changing x and this can be taken at any position because the correct end of a straight line is constant everywhere at any point in that line so what we're going to get here is equal to neck y is equal to negative 609 negative 609 2 .2 x plus 27 .136 in other ways, we're going to get lean k, this is kp being equal to negative 6092 .2, 1 over t, plus 27 .136...