00:01
So for this problem, we have the formation of water that looks like this.
00:10
And our goal is to find which of the diagrams shows the correct products and reactants after the reaction is complete.
00:18
So we do know a couple of things.
00:20
We know that we are dealing with three moles of oxygen as well as three moles of hydrogen.
00:28
So the first thing that we have to do is you need to find the limiting reactant so we can then determine how much of which reactant is left over and how much of the much is used.
00:35
So let's first start with our 3 moles of 02.
00:38
We want to find how many moles of h2 are required to use up all of those 3 moles.
00:44
So if you look at the multiple to ratio here in the reaction, if we want to use 1 mole of oxygen gas, we need 2 moles of hydrogen gas with it.
00:53
So our multiple ratio is 2 to 1.
00:58
And when you multiply this through, we'll get that 6 moles of hydrogen gas will be used up.
01:05
But we have 8 moles of hydrogen gas to begin with, meaning that our excess reactant is hydrogen, and all of the oxygen will be used up.
01:14
So we know that in our final answer, no oxygen will be used...