Question

Consider the reaction X2(g)-2 X(g). When a vessel initially containing 755 torr of X2 comes to equilibrium at 298 K, the equilibrium partial pressure of X is 103 torr. The same reaction is repeated with an initial partial pressure of 748 torr of X2 at 755 K; the equilibrium partial pressure of X is 532 torr. Find H for the reaction.

Name: Problem 97, Chapter 18: Chemistry: Structure and Properties
Uploaded: 2019-12-30T09:54:49-08:00
Duration: 1 min 15 s
Channel: Aadit Sharma
Description: Consider the reaction X2(g)-2 X(g). When a vessel initially containing 755 torr of X2 comes to equilibrium at 298 K, the equilibrium partial pressure of X is 103 torr. The same reaction is repeated with an initial partial pressure of 748 torr of X2 at 755 K; the equilibrium partial pressure of X is 532 torr. Find H for the reaction.

   Consider the reaction X2(g)-2 X(g). When a vessel initially containing 755 torr of X2 comes to equilibrium at 298 K, the equilibrium partial pressure of X is 103 torr. The same reaction is repeated with an initial partial pressure of 748 torr of X2 at 755 K; the equilibrium partial pressure of X is 532 torr. Find H
for the reaction.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Chapter 18, Problem 97

Instant Answer

Solved by Expert Aadit Sharma

12/30/2019

Step 1

We know that 1 atm pressure is equal to 760 torr. So, the partial pressure of X gas at equilibrium 103 torr can be converted to atm as follows: \[103 \, \text{torr} = \frac{103}{760} \, \text{atm} = 0.136 \, \text{atm}\] Similarly, the initial partial pressure of Show more…

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Consider the reaction X2(g)-2 X(g). When a vessel initially containing 755 torr of X2 comes to equilibrium at 298 K, the equilibrium partial pressure of X is 103 torr. The same reaction is repeated with an initial partial pressure of 748 torr of X2 at 755 K; the equilibrium partial pressure of X is 532 torr. Find H for the reaction.