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Hello everyone, let us do the following question.
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Here we have to consider the single phase 3 wire system.
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We have to find the current in the neutral power and complex power supplied.
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We have to find current in neutral current and complex power supplied.
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Here we will say l is equal to 50 millie henry.
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This is equal to j omega l.
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If we'll put value j omega is 2 pi into 60, this is 50.
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50 into 10 raised to 4 minus 3.
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We will write this value is j 18 .85.
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Now this is the consider.
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This is mesh 1, this is 2 and this is 3.
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Now we apply kbl to the 3 meshes.
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Now we apply, now we apply kbl to 3 meshes.
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Now we apply kbl.
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From first we will get 23 i1 minus 2 i2 minus 20 i3 is equal to 1115 from second minus 2 i 1 plus 33 i 2 minus 30 i 3 minus 30 i 3 is equal to 115 here minus 20 i 1 minus 30 i 2 plus here 65 plus j 18 .85 i 3 i 3 i 3 i 3 is equal to 0...