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Consider the thermal decomposition of $\mathrm{CaCO}_{3}.$$\mathrm{CaCO}_{3}(s) \rightleftharpoons \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)$The equilibrium vapor pressures of $\mathrm{CO}_{2}$ are $22.6 \mathrm{mmHg}$ at $700^{\circ} \mathrm{C}$ and $1829 \mathrm{mmHg}$ at $950^{\circ} \mathrm{C}.$ Calculate the standard enthalpy of the reaction. [Hint: See Problem 17.51(a).]

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$\triangle$$H^{\circ}=17.4 \times 10^{5} \mathrm{J} / \mathrm{mcol}$

Chemistry 102

Chapter 17

Entropy, Free Energy, and Equilibrium

Thermodynamics

University of Central Florida

Drexel University

University of Kentucky

Lectures

00:42

In thermodynamics, the zeroth law of thermodynamics states that if two systems are in thermal equilibrium with a third system, they are also in thermal equilibrium with each other.

01:47

A spontaneous process is one in which the total entropy of the universe increases. In a spontaneous process, the system will move from an ordered state to a disordered state, such as from ice to water, or from a solid to a gas. The concept of spontaneity was introduced by Rudolf Clausius in 1850.

04:15

Consider the thermal decom…

03:44

Consider the decomposition…

03:42

02:58

Calculate the heat of deco…

solution for the book problems for the region. Year C A C 03 in solar state toe calcium oxide in soil State plus Co two Okay, in the assisted the L K P is equal to PCO two. Okay, No, behave. You know you're okay. Nature lock into care two divided by care one is it? Well, Tau Delta. It's not divided by our into one appointee. One minus one appointee to is it will to Delta. It's not divided by all into t two minus t one divided by the one into t two. Yeah, nature log into 1827 divided by 2.6 Is able to delta h not divided by a 314 into 123 My knees 973 Divided by 12 to 3.973 Mhm. Oh, Delta, it's not is equal to 1.74 multiplied. Can rest to the power five child for more Yeah,

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