Question
Consider the transistor described in Problem 12.3. (a) For a common-base current gain of $\alpha=0.9850$, determine the common-emitter current gain [note: $\beta=\alpha /(1-\alpha)]$.(b) Determine the emitter and base currents corresponding to the collector currents determined in Problem 12.3. ( $c$ ) Repeats parts ( $a$ ) and ( $b$ ) for a common-base current gain of $\alpha=0.9940$.
Step 1
The formula to calculate $\beta$ is given as $\beta=\alpha /(1-\alpha)$. For $\alpha=0.9850$, we have: \[\beta_1 = \frac{0.9850}{1-0.9850} = 65.7\] For $\alpha=0.9940$, we have: \[\beta_2 = \frac{0.9940}{1-0.9940} = 165.7\] Show more…
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