Consider the unbalanced equation for the neutralization of...

Consider the unbalanced equation for the neutralization of acetic acid:
HC2H3O2(aq) + Ba(OH)2(aq)-H2O(l ) + Ba(C2H3O2)2(aq)

Balance the equation and determine how many moles of Ba(OH)2 are required to completely neutralize 0.461 mole of HC2H3O2.

Transcript

0:00 Okay.

00:01 Chapter seven section problem thirty six.

00:05 The question is considered the unbalanced equation for the neutralization of acetic acid and shown is h c to h three o two plus b a o.

00:16 H.

00:16 Two on goes to water, plus b a c to a ceo, too.

00:22 Two.

00:23 Okay, so we're supposed to balance this saying now what i see when i look at this as i see this sea to h three o two, which is the acid tate of this acetic acid, this acetic acid.

00:38 Well, then, once you lose that proton, then it's acid tate.

00:41 So this is like hydrogen acid ate, and that's repeated over on the other side.

00:44 And that's, you know, this is a there's a double displacement reaction, actually, between the hydrogen and the barium, so you can treat that whole thing as a unit.

00:56 And once you kind of recognize that it actually kind of simplifies this whole thing.

01:00 So so let's let me show you what i mean by that.

01:02 So if i was going to write this, you know, if you could be like a judge acid tate, you know, a sea we'll say that's equus.

01:16 Um, plus barium hydroxide.

01:30 It is going to go water.

01:33 And again this berry, um, but again, to kind of simplify things saved myself.

01:39 A lot of, you know, headache.

01:43 I'm just going treat that as a cz an ion, because that's what it is.

01:48 Okay.

01:48 And then we got to us.

01:50 So this this already looks a little bit more manageable.

01:54 So now let's balance this thing.

01:55 Okay, so let's look for things that are different.

01:57 The barium zahraa are the same money side.

01:59 We do have different amounts of that a c that group.

02:02 Ok, i've got two on the right, so i have one on laugh.

02:06 So if i multiply by two now, there's a balance, and then i move on to the thing that i changed to the hydrogen is then i'll get two on the left, two on the right.

02:14 That's fine.

02:14 Oxygen.

02:15 This is the next thing that's different, maybe.

02:18 Okay, so i've got one on the right, two on the left, so i actually need to multiply this whole thing by two.

02:25 Now, this is two and this is two.

02:30 So what did i switch when i multiply that the hydrogen is right? okay, so now i need to do that.

02:35 Action...