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Consider this question: What is the molarity of KMnO_ in a solution of 0.0908 $\mathrm{g}$ of $\mathrm{KMnO}_{4}$ in 0.500 $\mathrm{L}$ of solution?(a) Outline the steps necessary to answer the question.(b) Answer the question.

(a) 1 Find the molar mass of $\mathrm{KMnO}_{4}$2) Calculate the number of moles by dividing the known mass by the molar mass.3) Calculate the molarity by dividing the number of moles by the volume (in liters) of the solution.(b) $1.15 \times 10^{-3} \mathrm{M} \mathrm{KMnO}_{4}$

Chemistry 102

Chemistry 101

Chapter 3

Composition of Substances and Solutions

Solutions

Composition

Rice University

Drexel University

University of Maryland - University College

Lectures

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and this question were asked to determine the polarity off 0.908 grams of potential for magnate in 0.5 leaders off solution. So the polarity, which is essentially the concentration, is given by no unit volume and the move off the substance it's usually given by the mass divided by the molar mass. So in order to complete hilarity, all we need to do is find the number of bowls and divide that by the volume. So the mass we've been given its 0.908 grams the polarity of protesting for man beats. Don't expect you to complete this. The melody I calculated it was 15 8.0 32 grams more, right? It's actually just to the summation. Look at the periodic table final, but the more massive potassium is at that to myself. Manganese and other 24 times Camilla. Muscle oxygen. You should end up with 15.32 How we divide this result by the falling been given lolly Baz 0.5 leaders. So when solved, the worldly I attained for the polarity Well, this potential for magnates solution is 1.15 extensive. The par when I was three, well leader

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