00:01
In this question we've been given three steps, a three -step mechanism in which cl2 is at equilibrium with 2 cl, and then the cl reacts with chcl 3 to form hcl and ccl 3 and we then have another cl reacting with ccl3 to form ccl4.
00:26
So we need to determine the overall reaction which is just the sum of step one, step two and step three.
00:34
So if we are to do this, we're going to have an overall reaction that can be written as cl2, cl2 plus ch, cl3 forming cl and ccl4.
00:54
So what we just did here is to, for example here we've got our cl and it comes out with one of the cl also have another cl which cancels out with the remaining cl.
01:09
We also have ccl 3 here that cancels out with this ccl 3.
01:14
So what we are left with is cl, chcl3, and we have our hcl in the products and ccl.
01:21
So this is our overall chemical reaction.
01:25
Now if we are to look at this, the intermediates are produced and consumed by the reaction.
01:30
So this is what we've been canceling out here.
01:34
These are the intermediates.
01:37
So the intermediates we have cl.
01:41
We also have c, c, cl3...