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We want to conduct a kai squared test to variance and construct confidence intervals as follows.
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We have a population x with variance sigma squared equals 42 .3 for the population.
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A random sample of size n equals 23 has sample variance 46 .1.
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First, in one, we want to test the claim that sigma squared is greater than 42 .3 at 5 % significance.
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We have to proceed through steps a through e listed here to do so.
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So first, step a is to state alpha, the hypotheses.
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So our alpha value is our confidence level, our hypothesis.
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Are given, it's our known variance versus our claim.
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So we have alpha equals 0 .05, h0 sigma squared equals 42 .3, h .a sigma squared is greater than 42 .3.
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And b, we calculate the kai square value, the degree of freedom, and state the assumptions we make for x.
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So kai squared is an n minus 1 s squared over sigma squared, which is 23 .98, plugging in the values above.
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The degree of freedom is n minus 1 equals 22, and we have to assume that x is normally distributed...