00:01
We are given the following lewis structure and we are asked to respond to four questions.
00:07
Our first question, a, is, does this lewis structure depict a neutral atom or an ion? in order to do this, let's first figure out how many electrons are available from the atoms.
00:37
And our atoms are c, h, and o.
00:42
We have three carbons, three hydrogens, and two oxygens.
00:46
Let's multiply each one of these by their valence electrons.
00:51
Carbon has 4, hydrogen as 1, oxygen as 6.
00:58
Is 12, 3, and 12? if we add these, we get 27 electrons.
01:06
That's how many electrons we have available.
01:09
Now let's figure out how many electrons we have.
01:17
And in order to do that, we're going to highlight all of our electrons.
01:21
Remember each bond, each line represents two electrons, so i'm going to count by two's.
01:25
2, 4, 6, 8, 10, 12, 14, 16, 18, then our individuals are unbonded.
01:37
20, 22, 24, 26, 28.
01:43
We have 28 electrons, which means that this is an ion with a 1 minus charge.
01:57
That's letter a.
02:00
B asks us the hybridization for each c.
02:18
And for the hybridization for each c, let's do, let's look at our bonding sites.
02:25
On our first carbon, we have 1, 2, 3, so that's an sp2...