00:01
So first we have that the velocity of 4 part a, the velocity of car a is equaling 12 over 6.
00:08
So this is equaling 2 meters per second.
00:12
And we can then say that with an initial x value of 20 meters, we can say that the x position of car a, when t is equaling 4 seconds, would be equaling 28 meters.
00:28
So we can say then that 28 meters equals 12 meters per second multiplied by t plus one -half times the acceleration of carb times t squared.
00:51
And here t is equaling 4 .0 seconds where the acceleration of b is then equaling negative 2 .5 meters per second squared.
01:03
So that'll be for part a.
01:08
Now for part b, we can say, here the question is that using the value obtained for the acceleration for b in part a, are there other values where the position of car a is equaling the position of car b? and so what this essentially means is that 20 plus 2t must be equaling 12t plus 1 half the 1 half times the acceleration of b times t squared now we know that if t is equaling 4 .00 4 .0 seconds this is going to hold true now are there any other are there any other values of t where this statement holds true given that again, the acceleration of b is negative 2 .50 meters per second squared.
02:04
Now, here, there are two distinct routes unless the discriminant is zero...