00:02
In problem, 13, first we are going to confuse a square for the given metcits a.
00:18
That is a square is equal to, a times a, and this is equal to, since metcute a is 0, 0, 0, 0, 0.
00:44
0 0 and the third column is 02 0 the 4 column is the 4th column is minus 1 0 to 0 times matrix a the 1 the 1 and 2 -0 -0 -0 -2 -0 -0 -0 -0 minus 1 -0 -0 -0 -0 -0.
01:35
To find the product, first we write the dimensions of the matrix, since the first matrix is a color 4x4, and the dimensions of the second matrix.
01:55
Are 4x4.
01:57
That is the 2 million increase are equal.
02:01
So the 2 matrices are comfortable for multiplication since the number of columns in the first matrix are equal to the number of rows in the second matrix.
02:16
Now we can put the product right here, multiplying r1 with the corresponding increase of the first column in the second matrix, we get 0 and the product of r1 is c2 is 0, product of r1 c2 is 0, product of r1 c2 is 4, and proto of r1 c4 is 0.
03:14
Now the product of r2c1 is also 0.
03:20
R1 6r2 c2 is 0.
03:27
R2 c3 is 0.
03:33
R2 c4 is equal to 4...