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Construct a nondiagonal $2 \times 2$ matrix that is diagonalizable but not invertible.

Thus $A$ has two distinct eigenvectors.So it has two linearly independent eigenvectors.Hence by diagonalization theorem the above matrix is diagonalizable but not invertible.

Calculus 3

Chapter 5

Eigenvalues and Eigenvectors

Section 3

Diagonalization

Vectors

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Give an example of a $2 \t…

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okay, That's not a equal 11 serves up. So based on this, if you take a term in it, uh, a minus, You know that I get the city Could set of Terminix of one minus Lambda one. So and then the lambda that has been negative. Landa Times one minus lambda. Is it good? So we have to again, Really? That's lying is he could still win one. And the Matrix is diagonal Izabal based on their seven, but this is clearly not inevitable.

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