Construct a table like Table 20-1 for eight molecules. |...

Name: Problem 45, Chapter 20: Fundamentals of Physics
Uploaded: 2021-08-03T16:53:21-08:00
Duration: 7 min 8 s
Channel: Vipender Yadav
Description: Construct a table like Table 20-1 for eight molecules.

Key Concepts

Molecular Structure Representation

This concept involves depicting the arrangement of atoms, bonds, and functional groups within a molecule. It focuses on how molecules are drawn or modeled, often using symbols and notations to represent different atoms and the connections between them. Understanding molecular structure is fundamental in chemistry as it determines the physical and chemical properties of the substance.

Tabular Organization of Chemical Data

This concept refers to the method of organizing chemical information into tables for clarity and ease of comparison. In a tabular format, each row typically represents a different molecule and each column corresponds to a specific property or characteristic, such as molecular formula, structure, size, or reactivity. This structured approach aids in summarizing, analyzing, and communicating data effectively within the field.

Comparative Analysis Through Data Presentation

This concept is about using organized data, such as that in a table, to compare and contrast different molecules on various parameters. It helps in identifying trends, similarities, and differences among the molecules, which is crucial for drawing conclusions in research and problem-solving within chemistry. Comparative analysis provides insights into structure-property relationships and can guide further experimental or theoretical investigations.

Transcript

00:01 Now in this question we need to construct a table just like the table 20 -1 which is constructed in the book this table was constructed for six molecules but in this question we have to consider eight molecules and then we have to construct this table now in the first configuration we are taking that all molecules is in the first compartment so let this be the first compartment and this one is the second compartment so in one we have eight because all molecules are in the first compartment so this is 8 number of molecules in the second compartment is 0 so that will be 0 now next we're going to calculate w and w is basically the multiplicity of the configuration which is calculated by using the formula w is equals to n factorial divide by n1 factorial times n2 factorial now n we are given in the equation to be 8 now n in the first configuration we have 8 so let me put the values this is 8 factorial divide by n1 is also 8 so 8 factorial n2 we have 0 so that will be 0 factorial now 0 factorial is 1 so we are left with 8 factorial over 8 factorial which is equals to 1 so w we have calculated as 1 now next we're going to calculate the entropic corresponding to this configuration which is calculated using the formula is equals to k times natural log w now k here is a constant and its value we have 1 .38 times 10 to the power minus 23 jule per kelvin so we can put the values now in this formula to calculate entropic corresponding to this first configuration so k we have 1 .38 times 10 to the power minus 23 multiply with natural log w so w we have 1 so that will be 1 natural log 1 is 0 so the answer would be 0 so the entropy for the first configuration will be 0 now next we are taking that number of molecules in the second sorry in the first compartment is 7 and in the second compartment it is 1 so n1 in this case it will be 7 and n2 will be 1 now we can put the values here this this capital end remains the same and n1 changes to 7 so 7 factorial and this one is 1 factorial now we can simplify this so 8 times 7 factorial we can write this way also divide by 7 factorial multiplied with 1 factorial so this one and this one will cancel it out and we'll get 8 so this w we have 8 and now next we're going to calculate this is the entropy now here we see that this key remains the…

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