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Construct Your Own ProblemConsider a person outdoors on a cold night. Construct a problem in which you calculate the rate of heat transfer from the person by all three heat transfer methods. Make the initial circumstances such that at rest the person will have a net heat transfer and then decide how much physical activity of a chosen type is necessary to balance the rate of heat transfer. Among the things to consider are the size of the person, type of clothing, initial metabolic rate, sky conditions, amount of water evaporated, and volume of air breathed. Of course, there are many other factors to consider and your instructor may wish to guide you in the assumptions made as well as the detail of analysis and method of presenting your results.

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Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

University of Michigan - Ann Arbor

Simon Fraser University

University of Sheffield

Lectures

02:20

A solid, liquid, or gas is…

06:13

Matter is a state of aggre…

03:32

Consult Multiple-Concept E…

05:23

Even at rest, the human bo…

01:57

$\because$ Predict/Calcula…

04:51

A resting adult of average…

08:48

Construct Your Own Problem…

02:34

The excess internal energy…

05:42

A person inhales and exhal…

02:30

Multiple-Concept Example 8…

02:55

The thermal conductivities…

02:25

(a) Calculate the rate at …

$\cdot$ Heat loss during b…

03:42

$\bullet$ Basal metabolic …

01:41

04:13

Overall, 80$\%$ of the ene…

03:20

$\bullet$ Consider a doubl…

04:57

Heat Loss During Breathing…

04:10

In very cold weather a sig…

02:27

Consider two states of atm…

03:34

Consider two identical bui…

04:40

Consider a poor lost soul …

power at which energy gets metalized is equal to the power at which the radiation energy is gained. We just given by E Sigma a the fourth and in this case, this time because the temperature of the body is changing from G B to D room. So we have to take the difference in the fourth power off the temperatures corresponding temperatures to match it in the form off the equation. So writing it again b m equals E sigma a T body forth minus t room fault. So the body forth minus D room fort is given by power coming from the metal Buddhism divided by E sigma A. So the temperature of the body will come out to the temperature of the room to the fort. Dust power Bi meta modernism divided by E. Sigma A everything raised to the one foot off the power. Now the room temperature is given by or were trying to find ah, body temperature room temperature over here. So the equation got media artist as the room temperature Toby db Food minus the the start. Over here, the body temperature is 34 C, so that's 2 73 plus 34 in Galvin for power minus power due to metabolic is, um, ese 115 Jules for a second. Divided by M acidity, 0.7 sigma is given by 5167 times tend to the native eight times the area is 1.4 major squared. Other feet raced to the one foot off power. On these thieves, the room temperature Toby to 87.3. Kevin are to 87.3, minus 2 73 C equals 14.3 daily centered.

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