00:01
So in this problem, we're looking at another linear application.
00:03
We're actually told in this case, right, that we're talking about things in terms of t, right, where t represents our time, the number of years since 1980.
00:14
And our output represents our cpi, our consumer price index.
00:19
So one of the things that we know is it was in 1983.
00:24
And again, we're talking about years since 1980.
00:26
So three years after 1980, the cpi was 100.
00:33
In 2008, so 2008, and to think about this, right, if we want to know how many years, it was 28 years from 1980, the index would be 215 .3.
00:50
Now we have two points, and considering that it's approximately linear, we can write an equation to represent this situation.
00:58
So we're going to look at the changes of the ys over the changes of the x's, which will give us our slower.
01:03
So in this case, i'm going to take 215 .3 and subtract 100, which is 115 .3.
01:10
Then i'm going to take 28 minus 3, which is 25.
01:14
So that's going to give us an approximate slope of 4 .612.
01:22
So y equals 4 .612x plus b.
01:28
I'm going to use the point here.
01:29
So 100 equals 4 .612 times 3 plus b.
01:37
So that's 100 is equal to 13 .836 plus b.
01:43
So 100 minus that 13 number is going to give us a b value...