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Contact lenses. Contact lenses are placed right on the eyeball, so the distance from the eye to an object (or image) is the same as the distance from the lens to that object (or image).A certain person can see distant objects well, but his near point is 45.0 $\mathrm{cm}$ from his eyes instead of the usual 25.0 $\mathrm{cm} .$ (a) Is this person nearson nearsighted or farsighted? (b) What type of lens (con-verging or diverging is needed to correct his vision? (c) If the correcting lenses will be contact lenses, what focal length lens is needed and what is its power in diopters?

a) farsightedb) converging lensc) $+1.78$ diopters

Physics 102 Electricity and Magnetism

Physics 103

Chapter 25

Optical Instruments

Electromagnetic Waves

Reflection and Refraction of Light

Rutgers, The State University of New Jersey

University of Washington

Hope College

University of Sheffield

Lectures

02:30

In optics, ray optics is a…

10:00

In optics, reflection is t…

05:47

Contact lenses are placed …

04:45

A person can see clearly u…

04:43

A particular patient’s eye…

02:14

A person sees clearly wear…

01:39

$\cdot$ A person can see c…

03:10

04:57

Suppose that the lens syst…

03:53

A person with a nearsighte…

03:17

An individual is nearsight…

03:18

A cataract - impaired lens…

04:46

(a) Where is the near poin…

02:39

02:00

What focal length should a…

05:34

A patient can’t see object…

02:50

The near point of a person…

02:04

03:57

.. Ordinary glasses. Ordin…

12:58

A nearsighted man cannot c…

07:24

01:24

Suppose the distance from …

All right. So Ah, in this case, part for parts. And we should figure out if it is Ah, far side of this person is far sighted or near sighted and on DH. So the near point is greater than 25 centimeters. Ready Importance. 45 centimeters on DSO that gives us on. And so that means the image is formed behind the retina. And when that happens, you have farsighted vision. Finish formed in front of them to written up. In other words, their point is less than 25 centimeters. You know, you'd be near sight. Okay, So a virtual image is forming at the near point in this case. And so from the text, we know that to correct for farsightedness we have to use conversion lenses which can produce the virtual of image on the other side. Damage on the other side off uh, the lens, which is the cornea on DSO for focal in't. We used formula for focal length, just won over Africa. Lt's one over object distance plus one over image distance. And so that's one of her. The 25 centimetres minus one over 45 centimeters. Because, remember, image is forming on the other side of the lens as the object. And so this means that the focal length is UH plus 56.2 centimetres and notice that it's positive. So it's a converging lens and some power will be won over focal ink in meters. So that would be one of her 10.562 meters. And that gives us plus 1.78 Diop tres and that's it.

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